13x^2-2=0

Solution for 13x^2-2=0 equation:

13x^2-2=0

a = 13; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·13·(-2)
Δ = 104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{104}=\sqrt{4*26}=\sqrt{4}*\sqrt{26}=2\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{26}}{2*13}=\frac{0-2\sqrt{26}}{26}
=-\frac{2\sqrt{26}}{26}
=-\frac{\sqrt{26}}{13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{26}}{2*13}=\frac{0+2\sqrt{26}}{26}
=\frac{2\sqrt{26}}{26}
=\frac{\sqrt{26}}{13}
$